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The amount of ${Na}_{2} {CO}_{3}$ present in 100 mL of 0.1M ${Na}_{2} {CO}_{3}$ solution is

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2.12 g

0.53 g

1.06 g

5.3 g

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detailed solution

Correct option is C

Volume of solution, V $= 100 mL$

Concentration of ${Na}_{2} {CO}_{3}$ $= 0.1 M$

GMW of ${Na}_{2} {CO}_{3} = 106 g/mol$

Weight of ${Na}_{2} {CO}_{3} = ?$

From the formula of molarity,

$M = \frac{w}{GMW} \times \frac{1000}{V in mL}$

$\Rightarrow w = \frac{M×GMW}{1000} \times V in mL$

Substitute all known data in the above equation to find weight of ${Na}_{2} {CO}_{3}$ .

$Weight {of Na}_{2} {CO}_{3}, w = \frac{0.1 \times 106 \times 100}{1000}$

$∴ w = 1.06 g$

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The amount of Na2CO3 present in 100 mL of 0.1M Na2CO3 solution is