The chief ore of zinc is the sulfide, ZnS. The ore is concentrated by a froth floatation process and then heated in air, which converts the ZnS to ZnO.2ZnS + 3O₂ → 2ZnO + 2SO₂ (75%  conversion)ZnO + H₂SO₄  → ZnSO₄ + H₂O (100% conversion ) 2ZnSO₄ + 2H₂O → 2Zn + 2H₂SO₄ + O₂ (80%  conversion)The mass of Zn obtained from a sample of ore containing 292.2 kg of ZnS will be :

# The chief ore of zinc is the sulfide, ZnS. The ore is concentrated by a froth floatation process and then heated in air, which converts the ZnS to ZnO.2ZnS + 3O₂ → 2ZnO + 2SO₂ (75%  conversion)ZnO + H₂SO₄  → ZnSO₄ + H₂O (100% conversion ) 2ZnSO₄ + 2H₂O → 2Zn + 2H₂SO₄ + O₂ (80%  conversion)The mass of Zn obtained from a sample of ore containing 292.2 kg of ZnS will be :

1. A
117.72 kg
2. B
214.62 kg
3. C
145.23 kg
4. D
166.55 kg

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### Solution:

2ZnS + 3O₂ 2ZnO + 2SO₂
​2ZnO + 2H₂SO₄ 2ZnSO₄ ​+ 2H₂O
2ZnSO₄ + 2H₂O$\to$ 2Zn + 2H₂SO₄ + O₂
​It can be observed that one mole of ZnS gives 1 mole of Zn.
The molar masses of Zn and ZnS are 65.37 g/mol and 97.47 g/mol.
The mass of zinc that can be obtained from
292.2 kg of ZnS is × 292.2 ×× $\frac{100}{100}$ $×\frac{80}{100}$ =117.72 kg.

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