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The decreasing values of bond angles from NH3 to SbH3 down the group 15 of the periodic table is due to

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a
increasing bp–bp repulsion
b
increasing p-orbital character in sp3
c
decreasing lp-bp repulsion
d
decreasing electronegativity of central atom

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detailed solution

Correct option is D

The H - M - H bond angle is less than the original 1090, tetrahedral bond angle (H -N -H) in Ammonia 1060
because of greater repulsion between one pair an a on pair than between two bond pairs of electrons. Because electro-negativity of M decreases from N to Bi, the bond pair lie farther away from the central atom, and the lone pair causes greater distortion of bond angle. Thus H-P-H bond in Phosphine.
 

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