The difference between Cp and CV of 0.2 mole of an ideal gas is about

The difference between $C_{p}$ and $C_{V}$ of 0.2 mole of an ideal gas is about

A
$8.314 J K^{- 1}$
B
$4.157 J K^{- 1}$
C
$1.663 J K^{- 1}$
D
$3.333 J K^{- 1}$

Solution:

$C_{p} - C_{V} = n R = (0.2 mol) (8.314 {JK}^{- 1} {mol}^{- 1}) = 1.666 {JK}^{- 1}$

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