ChemistryThe E0 (in V) at 298 K of the given cell is:A(s)A3+‖B2+B(s)2A(s)⟶2A3++6e-, E°=-2x V3B2++6e-⟶3B(s), E°=3y V

The E0 (in V) at 298 K of the given cell is:

A(s)A3+B2+B(s)

2A(s)2A3++6e-, E°=-2x V

3B2++6e-3B(s), E°=3y V

  1. A

     y-x
     

  2. B

    y + x
     

  3. C

     3y + 2 x
     

  4. D

    3y - 2x

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    Solution:

    Ecell° =Ecathode-Eanode          =3y V-(-2x V) = 3y+2x V

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