The edge length of face centred unit cubic cell is 508 pm. If the radius of the cation is 110 pm, the radius of the anion is

The edge length of face centred unit cubic cell is 508 pm. If the radius of the cation is 110 pm, the radius of the anion is

A
285 pm
B
398 pm
C
144 pm
D
618 pm

Solution:

Distance between centres of cation and anion

$\begin{array}{l} = \frac{d}{2} = \frac{508}{2} = 254 pm \end{array}$

$r_{c} + r_{a} = 254 pm$ or $110 + r_{a} = 254$ or $r_{a} = 144 pm$

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