The electrons identified by quantum number n and l

# The electrons identified by quantum number n and l

1. A

$n=4,l=1$

2. B

$n=4,l=0$

3. C

$n=3,l=2$

4. D

$n=3,l=1$

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### Solution:

Energy of an electron in an atom increases with increase in the value of $n+l.$For the same value of $n+l.$The energy is larger for the larger value of n. Hence, we have

Choice (i); $n+l=4+1=5$      Choice (iii);  $n+l=3+2=5$

Choice (ii); $n+l=4+0=4$    Choice (iv); $n+l=3+1=4$

Hence, the correct order of increasing energy is (iv) < (ii) < (iii) < (i)

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