The electrons, identified by quantum numbers n and I  (i) n=4,=1 (ii) n=4,=0 (iii) n=3,=2 (iv) n = 3 , l = 1 can be placed in order of increasing energy, from the lowest to highest, as

  1. A

    ( iv )<( ii )<( iii )<( i )

  2. B

     (ii )<( iv )<( i )<( iii )

  3. C

     (i) < (iii) < (ii) < (iv) 

  4. D

     (iii) <(i)<( iv )<( ii )

    Join Our Infinity Learn's Learning Program!

    FREE Lve Classes, PDFs, Solved Questions, PYQ's, Mock Tests, Practice Tests, and Test Series!

    +91

    Verify OTP Code (required)


    I agree to the terms and conditions and privacy policy.

    Solution:

    Higher the value of (n + l), the higher is the energy.
    When (n + l) value is the same see value of n.
     

     (i)(ii)(iii)(iv)
    (n + l)(4+1)=5(4+0)=4(3+2)=5(3+1)=4

     (iv) <( ii )<( iii )<(i)

    Chat on WhatsApp

      Join Infinity Learn Regular Class Program!

      Sign up & Get instant access to FREE PDF's, solved questions, Previous Year Papers, Quizzes and Puzzles!

      +91

      Verify OTP Code (required)





      I agree to the terms and conditions and privacy policy.