The energy of an electron in the first Bohr orbit of a hydrogen atom is −2.18×10−18J. Its energy in the second orbit would be

The energy of an electron in the first Bohr orbit of a hydrogen atom is $- 2.18 \times 10^{- 18} J$ . Its energy in the second orbit would be

The expression of energy is

$E = \frac{1}{n^{2}}$ (constant).

Thus

$E_{2} = E_{1} (\frac{n_{1}^{2}}{n_{2}^{2}}) = (- 2.18 \times 10^{- 18} J) (\frac{1}{4}) = - 5.45 \times 10^{- 19} J$

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