The enol form of acetone, after treatment with D2O, gives

  1. A

    CH3C|=CH2            OD

     

  2. B

     

    CH3CCH3            O

  3. C

     

    CH2=C|CH2D             OH               

  4. D

     

    CD2=C|CD3             OD

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    Solution:

    CH3CCH3CH3C|=CH2D2OCH3C|=CH2            O                            OH                          OD

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