The frequency of radiation of wavelength 6000 Å is:

The frequency of radiation of wavelength 6000 Å is:

A
$3 .0 \times 10^{14} Hz$
B
$6 .0 \times 10^{14} Hz$
C
$5 .0 \times 10^{14} Hz$
D
$5 .0 \times 10^{15} Hz$

Solution:

$Frequency = \frac{C}{λ} = \frac{3 .0 \times 10^{8} {ms}^{- 1}}{6000 \overset{0}{A}}$

$= \frac{3 .0 \times 10^{8} {ms}^{- 1}}{6000 \times 10^{- 8} cm \times 10^{- 2} m / cm}$

$= \frac{3 .0 \times 10^{8}}{6 .0 \times 10^{- 7}} s^{- 1} = \frac{1}{2} \times 10^{15}$

$= 5 .0 \times 10^{14} s^{- 1} = 5 .0 \times 10^{14} Hz$

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