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The ionization energy of hydrogen atom is 1314 kJ mol1.The ionization energy of He+ ion is expected to be 

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a
1314 kJ mol1
b
2628 kJ mol1
c
3952 kJ mol1
d
5256 kJ mol1

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detailed solution

Correct option is D

Since EZ2/n2,we have

 E1He+E1(H)=4/11/1=4 E1He+=4E1(H)

Hence,

   IEHe+=4IE(H) =4×1314 kJ mol1 =5256 kJ mol1

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