The ionization energy of one mole of hydrogen atoms is about

A
1313 J
B
1313 kJ
C
1616 J
D
1616 kJ

Solution:

$IE = N_{A} R_{\infty} h c = (6.022 \times 10^{23} {mol}^{- 1}) (1.09678 \times 10^{7} m^{- 1}) (6.626 \times 10^{- 34} Js) (3 \times 10^{8} {ms}^{- 1}) = 1.313 \times 10^{6} J {mol}^{- 1} = 1313 kJ {mol}^{- 1}$

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