ChemistryThe mass of a non-volatile solute(in gm) of molar mass 40gmol- that should be dissolved in 114 g of octane to lower its vapour pressure by 20% is: (assume solution is dilute)

The mass of a non-volatile solute(in gm) of molar mass 40gmol- that should be dissolved in 114 g of octane to lower its vapour pressure by 20% is: (assume solution is dilute)

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    Solution:

    Assume that the vapor pressure of pure octane C8H18 is  pA° of pure solvent and the vapor pressure of octane after dissolving non-volatile solution is  80100pA.

    Applying formula:

    pA°-pApA°=XB pA°-pApA°=Moles of soluteMoles of solute+Moles of solvent

    When solution is dilute

    pA°-pApA°=nsolutensolvent

    Substitute the values:

    100-80100=mass of solute40 g/mol114 g114 g/mol mass of solute=8 g

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