The molar conductivities ΛNaOAc∞ and ΛHCl∞ at infinite dilution in water at 25 °Care 910 and 426.2 S cm2 mol-1' respectively. To calculate, ΛNOAc∞ the additional value required is - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

A
$Λ_{NaCl}^{\infty}$
B
$Λ_{H_{2} O}^{α}$
C
$Λ_{KCl}^{\infty}$
D
$A_{NaOH}^{\infty}$

Solution:

We have $Λ_{HOAc}^{\infty} = Λ_{NaOAc}^{\infty} + Λ_{HCl}^{\infty} + Λ_{NaCl}^{\infty}$ Hence, in addition to $Λ^{\infty} (NaOAc)$ and $Λ^{\infty} (HCl)$ we must have the value of $Λ^{\infty} (NaCl)$

The molar conductivities $Λ_{NaOAc}^{\infty}$ and $Λ_{HCl}^{\infty}$ at infinite dilution in water at 25 °Care 910 and 426.2 S ${cm}^{2} {mol}^{- 1}$ ' respectively. To calculate, $Λ_{NOAc}^{\infty}$ the additional value required is

Solution:

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