The momentum (in kg-m/s) of photon having 6 MeV energy is x×10-21;what is x

Solution:

$\begin{array}{l} E = (mc) . c or P = \frac{E}{c} \\ = \frac{6 \times 10^{6} \times 1 .6 \times 10^{- 19}}{3 \times 10^{8}} \\ = 3 .2 \times 10^{- 21} kgm / s \end{array}$

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