The number of atoms in 100 g of an fcc crystal with density d=10g/cm3 and cell edge equal to 100 pm is equal to

  1. A

    4×1025

  2. B

    3×1025

  3. C

    2×1025

  4. D

    1×1025

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    Solution:

    density =Z×Ma3×N

    M=ρ×a3×N0×10-30z

    =10×(100)3×(6.02×1023)×10-304=1.505gr

    Number of atoms in 100g=6.02×10231.505×100=4×1025

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