The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms?

  1. A

    4 g He

  2. B

    46 g Na

  3. C

    0.4 g Ca

  4. D

    12 g He

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    Solution:

    (a) 1 mol of He = 4 g = NA atoms
    or 4 g of He =44mol=1NA atom 
    (b) 1 mole of Na = 23 g = NA atoms  no.of moles = given mass  atomic mass 
    46 g of Na = 4623mol = 4623NA atoms = 2NA atoms
    (c) 1 mole of Ca = 40 g = NA atoms
    0.40g of Ca=0.4040mol=0.4040NA atoms
    = 0.01 NA atoms
    (d) 1 mole of He = 4 g = NA atoms
    12 g of He=124 mol = 124 NA atoms = 3NA atoms

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