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The number of electrons required to deposit 6.35 g of copper at the cathode during the electrolysis of an aqueous solution of copper sulphate will be (Given: Atomic mass of Cu= 63.5 u, NA is Avogadro constant)

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a
NA/20mol
b
NA/10mol
c
NA/5mol
d
NA/2mol

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detailed solution

Correct option is C

Amount of Cu to be deposited at the cathode is n=mM=6.35 g63.5 g mol1=0.10 mol

Since 2 electrons are required to convert Cu2+ ion into Cu, the amount of electrons required to deposit 0.10mol of Cu will be 0.20 mol. The number of electrons required will be (0.20mol) NA i.e. NA/5mol.

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