The number of isomers possible for disubstituted borazine, B3N3H4X2 is

Solution:

Borazine has a formula B₃N₃H₆ and has six reactive hydrogen ions. When it gets disubstituted with X, then it forms B₃N₃H₄X₂ and is called disubstituted borazine. This has four reactive hydrogen ions, therefore there are four ways through which 2X can arrange in B₃N₃H₄X₂. Therefore, the number of isomers in B₃N₃H₄X₂ is 4.

The number of isomers possible for disubstituted borazine, $B_{3} N_{3} H_{4} X_{2}$ is

Solution:

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