The number of isomers possible for disubstituted borazine, B3N3H4X2 is

  1. A

    3

  2. B

    4

  3. C

    6

  4. D

    5

    Join Our Infinity Learn's Learning Program!

    FREE Lve Classes, PDFs, Solved Questions, PYQ's, Mock Tests, Practice Tests, and Test Series!

    +91

    Verify OTP Code (required)


    I agree to the terms and conditions and privacy policy.

    Solution:

    Borazine has a formula B3N3H6 and has six reactive hydrogen ions. When it gets disubstituted with X, then it forms B3N3H4X2 and is called disubstituted borazine. This has four reactive hydrogen ions, therefore there are four ways through which 2X can arrange in B3N3H4X2. Therefore, the number of isomers in B3N3H4X2 is 4.

    Chat on WhatsApp

      Join Infinity Learn Regular Class Program!

      Sign up & Get instant access to FREE PDF's, solved questions, Previous Year Papers, Quizzes and Puzzles!

      +91

      Verify OTP Code (required)





      I agree to the terms and conditions and privacy policy.