The number of moles of lead nitrate needed to coagulate 2 mol of colloidal  [AgI]I is

  1. A

    2

  2. B

    1

  3. C

    1/2

  4. D

    2/3

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    Solution:

    2[AgI]I+Pb2+PbI2+2AgI Thus 2 mole of [AgI]I has two mole -ve charges, it is equivalent to total charge on Pb2+ of one mole of PbNO32.

     

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