The number of sodium atoms in 2 moles of sodium ferrocyanide is

  1. A

    12×1023

  2. B

    26×1023

  3. C

    34×1023

  4. D

    48×1023

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    Solution:

    As we know that, four sodium atoms are present in sodium ferrocyanide [Na4Fe(CN)6]
    Hence, number of Na atoms = No. of moles x number of atoms x Avogadro's number
    2 x 4 x 6.023 x 1023 = 48 x 1023

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