The oxide of a metal has 32% oxygen. Its equivalent weight would be

# The oxide of a metal has 32% oxygen. Its equivalent weight would be

1. A

34

2. B

32

3. C

17

4. D

8

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### Solution:

Let weight of metal oxide = 100 g

Weight of oxygen = 32 g

$\therefore$  Weight of metal = 100 - 32 = 68 mg

Equivalent weight of oxide = $\frac{\mathrm{wt}.\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}}\mathrm{metal}}{\mathrm{wt}.\text{\hspace{0.17em}\hspace{0.17em}}\mathrm{of}\text{\hspace{0.17em}}\mathrm{oxygen}}×8$

$=\frac{68}{32}\text{\hspace{0.17em}\hspace{0.17em}}×\text{\hspace{0.17em}\hspace{0.17em}}8=17$

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