The pressure exerted by a mass of ‘x’ mg resting on the area of 1.00cm2 is 1.00 Pa, then ‘x’ is

# The pressure exerted by a mass of ‘x’ mg resting on the area of 1.00${\mathrm{cm}}^{2}$ is 1.00 Pa, then ‘x’ is

1. A

10.300

2. B

10.308

3. C

1030

4. D

10.2

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### Solution:

Given data:

P=1Pa

$\mathrm{m}=\mathrm{x}×{10}^{-6}\mathrm{Kg}$

$P=\frac{\mathrm{ma}}{\mathrm{A}}$

$=\frac{\mathrm{mg}}{\mathrm{A}}$

$1=\frac{x×{10}^{-6}×9.8}{{10}^{-4}}$

${10}^{-4}=\mathrm{x}×{10}^{-6}×9.8$

$\frac{{10}^{-4}×{10}^{6}}{9.8}=x$

$x=\frac{{10}^{3}}{98}$

$x=\frac{1}{98}×{10}^{3}$

$\mathrm{x}=0.0102×{10}^{3}$

=10.2

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