ChemistryThe radius of 2nd orbit in  Be+3 ion is

The radius of 2nd orbit in  Be+3 ion is

  1. A

    Equals to the radius of ground state in H-atom

  2. B

    0.529A°

  3. C

    2 times to the radius of ground state in He+

  4. D

    3 times to the radius of ground state in Li+2 ion

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    Solution:

    γn=0.529×n2zA0

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