The radius of hydrogen atom in the ground state is 0.53Å ,the radius of Li2+ in the similar state is

The radius of hydrogen atom in the ground state is 0.53Å ,the radius of ${Li}^{2 +}$ in the similar state is

A
1.06Å
B
0.265Å
C
0.175Å
D
0.53Å

Solution:

The formula of radius calculation in the orbit is

$r_{n} = \frac{0.53 \times n^{2}}{Z} A^{°}$

Here, ‘n’ is orbit number and ‘Z’ is atomic number of an element.

For ${Li}^{2 +}$ ion, with Z = 3and n =1 , radius is

$r_{{Li}^{2 +}} = \frac{0.53 \times {(1)}^{2}}{3} = 0.176 A^{°}$

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