The rate constants of a reaction at 300K & 280K respectively are k1& k2 . Then

The rate constants of a reaction at 300K & 280K respectively are $k_{1} & k_{2} . Then$

A
$k_{1} = 20 k_{2}$
B
$k_{2} = 4 k_{1}$
C
$k_{1} = 4 k_{2}$
D
$k_{1} = 0.5 k_{2}$

Solution:

Temperature coefficient $Q = \frac{K_{300}}{K_{290}} = 2$

$\underset{k_{2}}{K_{280}} \underset{2}{\to} K_{290} \underset{2^{2}}{\to} \underset{K_{1}}{K_{300}}$

$\frac{K_{1}}{K_{2}} = 4 K_{1} = 4 K_{2}$

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