# The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is

1. A

1 : 4

2. B

7 : 32

3. C

1 : 8

4. D

3 : 16

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### Solution:

$\frac{{\mathrm{n}}_{{\mathrm{O}}_{2}}}{{\mathrm{n}}_{{\mathrm{N}}_{2}}}=\frac{\frac{\left({\mathrm{m}}_{{\mathrm{O}}_{2}}\right)}{\left({\mathrm{M}}_{{\mathrm{O}}_{2}}\right)}}{\frac{\left({\mathrm{m}}_{{\mathrm{N}}_{2}}\right)}{\left({\mathrm{M}}_{{\mathrm{N}}_{2}}\right)}}$
$=\left(\frac{{\mathrm{m}}_{{\mathrm{O}}_{2}}}{{\mathrm{m}}_{{\mathrm{N}}_{2}}}\right)\frac{28}{32}=\frac{1}{4}×\frac{28}{32}$

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