The ratio of masses of oxygen and nitrogen in a particular gaseous mixture is 1 : 4. The ratio of number of their molecule is

  1. A

    1 : 4

  2. B

    7 : 32

  3. C

    1 : 8

  4. D

    3 : 16

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    Solution:

    nO2nN2=mO2MO2mN2MN2
    =mO2mN22832=14×2832
    = 732

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