The solubility of sparingly soluble salt AxBy in water is given by the expression

A
$s = K_{s p}^{1 / (x + y)}$
B
$s = x^{x} y^{y} K_{s p}^{1 / (x + y)}$
C
$s = {(K_{sp} / x^{x} y^{y})}^{1 / (x + y)}$
D
$s = {(K_{sp} / x^{y} y^{x})}^{J / (x + y)}$

Solution:

$A_{x} B_{y} ⇌ x A^{y +} + y B^{x -}$ .Ifs is the solubility of the salt, then in solution, we will have

$\begin{matrix} A_{x} B_{y} ⇌ x A^{y +} + y B^{x -}; K_{sp} = {[A^{y +}]}^{x} {[B^{x -}]}^{y} = (x s)^{x} (y s)^{y}; This gives s = {(K_{sp} / x^{x} y^{y})}^{1 / (x + y)} \\ (x s) (y s) \end{matrix}$ ..

The solubility of sparingly soluble salt $A_{x} B_{y}$ in water is given by the expression

Solution:

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