The "spin-only" magnetic moment [in units of Bohr magneton, μB] of Ni2+ in aqueous solution would be (atomic number Ni = 28)

  1. A

    1.73

  2. B

    2.84

  3. C

    4.90

  4. D

    0

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    Solution:

    The expression of spin-only magnetic moment is L=n(n+2)μB

    The configuration of Ni2+ is (3d)8. It contains two unpaired electrons. Hence L=2(4)μB=2.83μB

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