The total number of gm-molecules of SO2Cl2 in 13.5 g of sulphuryl chloride is

A
0.1
B
0.2
C
0.3
D
0.4

Solution:

$Molecular weight of {SO}_{2} {Cl}_{2}$
= 32 + 32 + 2 x 35.5 = 135 gm
$∵ 135 gm of {SO}_{2} {Cl}_{2} = 1 gm molecule$
$∴ 13 .5 gm of {SO}_{2} {Cl}_{2} = \frac{1}{135} \times 13 .5 = 0 .1$

Related content

Appreciation Words

Wave Optics Mind Map

Alternating Current Mind Map for Class 12, JEE & NEET

Paramedical Courses After Class 10

Top Courses After 12th Science with PCM, PCB and PCMB

Subject Change Application in School and College

CBSE Class 10 Result 2024: Is the Release Date Early? Check Expected Schedule

Mizoram NEET Merit List 2023

Government Jobs After 12th Arts Stream

Chhattisgarh NEET UG Merit List 2023