The total number of nodes in an orbital is equal to the value of

The total number of nodes in an orbital is equal to the value of

A
$n$
B
$n - 1$
C
$n - 2$
D
$n + l - 1$

Solution:

Total number of nodes= (spherical+ angular) nodes $= n - l - 1 + l = n - 1$

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