The weight of a residue obtained by heating 2.76 g of silver carbonate is

The weight of a residue obtained by heating 2.76 g of silver carbonate is

A
2.76 g
B
2.98 g
C
2.16 g
D
2.44 g

Solution:

$2 {Ag}_{2} {CO}_{3} \overset{∆}{\to} 4 Ag + 2 {CO}_{2} + O_{2}$

$\begin{array}{ll} 2 \times 276 = 552 4 \times 108 \end{array}$

$∵ 552 gm$ silver carbonate gives silver = 432 gm

$∴ 2.76$ gm silver carbonategives

= $\frac{432 \times 2.76}{552} = 2.16 gm$

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