What is the concentration of copper sulphate (in mol L-1), if 80 g of it is dissolved in enough water to make a final volume of 3 L?

1. A

0.0167

2. B

0.167

3. C

1.067

4. D

10.67

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Solution:

Molar mass of CuSO4 = 63.5 + 32 + 64 = 159.5
Moles of CuSO4 $=\frac{80}{159.5}=0.50$
Volume of solution = 3 L
Molarity =

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