What is the equivalent mass of O2 in the following reaction, H2O+12O2+2e−⟶2OH−?

$What is the equivalent mass of O_{2} in the following reaction, H_{2} O + \frac{1}{2} O_{2} + 2 e^{-} ⟶ 2 {OH}^{-} ?$

Solution:

$Equivalent mass O_{2} = \frac{32}{4} = 8$ ,equivalent mass is always calculated with respect to one mole of substance.

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