What will be the molality of chloroform in the water sample which contains 15 ppm chloroform by mass?

A
1.25 x 10^-4 m
B
2.5 x 10^-4 m
C
1.5 x 10^-3 m
D
1.25 x 10^-5 m

Solution:

$15 ppm = \frac{15}{10^{6}} \times 10^{2} = 1 .5 \times 10^{- 3} g$
Molarity of CHCl₃ solution $= \frac{1 .5 \times 10^{- 3}}{100} \times \frac{1000}{119 .5}$
= 1.25 x 10^-4 m

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