What will be the ratio of volume of Al 27 13 nucleus to that of Na 23 11 ?

What will be the ratio of volume of ${}_{13}{Al}^{27}$ nucleus to that of ${}_{11}{Na}^{23}$ ?

A
$1.055$
B
$1.174$
C
Density of atoms should be known for calculations
D
$1$

Solution:

Ratio $= {(\frac{27}{23})}^{3} = 1.174$

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