When 0.2g of butanol was burnt in a suitable apparatus, the heat evolved was sufficient to raise the temperature of 200g of water by 5K. The heat of combustion of butanol in K.cal/mol is

# When 0.2g of butanol was burnt in a suitable apparatus, the heat evolved was sufficient to raise the temperature of 200g of water by 5K. The heat of combustion of butanol in K.cal/mol is

1. A

0.37

2. B

307

3. C

37

4. D

370

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### Solution:

0.2 g of butanol ----------------- 1000 cal

74g of butanol ------------------ ?

$\begin{array}{l}\frac{74×1000}{0.2}=370×{10}^{3}\mathrm{cal}/\mathrm{mol}\\ =370\mathrm{k}.\mathrm{cal}/\mathrm{mol}\mid \end{array}$

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