When Ferrous sulphate acts as reductant, its equivalent weight is

Solution:

Reductant is also known as reducing agent means it helps in the reduction process by losing electrons from itself.

In Ferrous sulphate, $$\text{FeS}{\text{O}}_{\text{4}}$$, iron (Fe) is present in +2 oxidation state and sulphur is present in the -2 oxidation state. When ferrous sulphate is present as reductant, it removes one electron and turns into +3 oxidation state.

Molecular weight of $$\text{FeS}{\text{O}}_{\text{4}}$$ is:
$$\begin{array}{c}\text{FeS}{\text{O}}_{\text{4}}=55.8+32+(4\times 16)\\ \text{FeS}{\text{O}}_{\text{4}}=151.8\end{array}$$

Equivalent weight of ferrous sulphate is
$$\text{FeS}{\text{O}}_{\text{4}}={\displaystyle \frac{151.8}{1}}=151.8$$
So, equivalent weight of ferrous sulphate is equal to the molecular weight of ferrous sulphate.