Which of the following arrangement of orbitals having quantum numbers (i) n = 4, l = 2 (ii) n = 5, l = 1 (iii) n = 4, l = 3 is correct regarding their relative energies?

Which of the following arrangement of orbitals having quantum numbers (i) $n = 4, l = 2$ (ii) $n = 5, l = 1$ (iii) $n = 4, l = 3$ is correct regarding their relative energies?

A
(i) <(ii)< (iii)
B
(i) <(iii)< (ii)
C
(ii) < (i) < (iii)
D
(ii) < (iii) < (i)

Solution:

Larger the value of $n + l$ ,larger the energy. For the same value of n +/, larger the value of n, larger the energy.

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