Which of the isoelectronic species has more electrons than neutrons?

Which of the isoelectronic species has more electrons than neutrons?

A
$O^{2 -}$
B
$Ne$
C
${Na}^{+}$
D
${Mg}^{2 +}$

Solution:

Each species contains 10 electrons. The number of neutrons are as follows:

$O^{2 -} : 16 - 8 = 8 Ne : 20 - 10 = 10 {Na}^{+} : 23 - 11 = 12 {Mg}^{2 +} : 24 - 12 = 12$

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