‘X’ grams sodium bicarbonate liberated sufficient carbondioxide which can completely oxidize 12 grams of coke, value of ‘X’ is

A
84 g
B
336 g
C
168 g
D
126 g

Solution:

$\begin{array}{l} {CO}_{2} (g) + C (s) \to 2 CO (g) \\ 1 mole 12 g \\ 2 {NaHCO}_{3} (s) \to {Na}_{2} {CO}_{3} (s) + H_{2} O (g) + {CO}_{2} (g) \\ (2 \times 84) g 1 mole \end{array}$

Related content

National Safe Motherhood Day 2024 (11th April)

Class 9 English Chapter 3 Beehive The Little Girl Worksheet

How to Join NDA After 12th: Eligibility, Physical Requirements, Important tips to crack NDA

Class 9 Chapter 2 English Worksheet – Sound of Music Worksheet

JEE Main 2024 April 9 Question Paper with Solutions- Shift 1, 2 Answer Key PDF

Class 9 English Chapter 1 Worksheet

UP Board 12th Result 2024, Check UP Board Class 12 Result Details

Gudi Padwa

JEE Main 2024 April 8 Question Paper with Solutions- Shift 1, 2 Answer Key PDF

CBSE Class 10 English Reported Speech Worksheet