Mathematicsβ‡’ π‘€π‘’π‘‘π‘–π‘Žπ‘› = 35.76A line 𝐷𝐸 is drawn parallel to base 𝐡𝐢 of β–³ 𝐴𝐡𝐢, meeting 𝐴𝐡 in 𝐷 and 𝐴𝐢 in at 𝐸. If2 π‘π‘š, find the length of 𝐴𝐸.


β‡’ π‘€π‘’π‘‘π‘–π‘Žπ‘› = 35.76

A line 𝐷𝐸 is drawn parallel to base 𝐡𝐢 of β–³ 𝐴𝐡𝐢, meeting 𝐴𝐡 in 𝐷 and 𝐴𝐢 in at 𝐸. If

2 π‘π‘š, find the length of 𝐴𝐸.

  1. A
     10π‘π‘š
  2. B
    2π‘π‘š
  3. C
     6π‘π‘š
  4. D
     12π‘π‘š 

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    Solution:


    𝐴𝐡
    𝐡𝐷

    = 4 π‘π‘š and 𝐸 =
     From the question we have,
    𝐴𝐡 = 4 π‘π‘š and 𝐢𝐸 = 2 cm
    𝐡𝐷
     Also, 𝐷𝐸 βˆ₯ 𝐡𝐢
     By the property of similar triangles,

    𝐴𝐷 π΄πΈ
    𝐴𝐡 = 𝐴𝐢
     β‡’ 1 βˆ’ 𝐴𝐷 = 1 βˆ’ 𝐴𝐸
    𝐴𝐡 π΄πΆ
     π΄π΅ βˆ’ 𝐴𝐷

    𝐴𝐢 βˆ’ 𝐴𝐸 π΅π· πΆπΈ
    β‡’ π΄π΅ =

    𝐴𝐢 β‡’ 𝐴𝐡 = 𝐴𝐢
     β‡’ 1  = 2
    4 π΄πΆ
    β‡’ 𝐴𝐢 = 8 cm

    𝐴𝐸 = 𝐴𝐢 βˆ’ 𝐢𝐸 = 8 βˆ’ 2
    𝐴𝐸 = 6π‘π‘š
     
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