Solution:
π΄π΅
= 4 ππ and πΈ =
π΄π΅ = 4 ππ and πΆπΈ = 2 cm
π΅π·
Also, π·πΈ β₯ π΅πΆ
By the property of similar triangles,
π΄π· π΄πΈ
π΄π΅ = π΄πΆ
β 1 β π΄π· = 1 β π΄πΈ
π΄π΅ π΄πΆ
π΄π΅ β π΄π·
π΄πΆ β π΄πΈ π΅π· πΆπΈ
β π΄π΅ =
π΄πΆ β π΄π΅ = π΄πΆ
β 1 = 2
4 π΄πΆ
β π΄πΆ = 8 cm
π΄πΈ = π΄πΆ β πΆπΈ = 8 β 2
π΄πΈ = 6ππ