∫01.5 x2dx is equal to

01.5x2dx is equal to

  1. A

    2

  2. B

    22

  3. C

    2+2

  4. D

    2

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    Solution:

    We have,

    01.5x2dx=01x2dx+12x2dx+21.5x2dx 01.5x2dx=010dx+11.51dx+212dx

    01.5x2dx=0+(21)+2(1.52)=22

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