Mathematics10[tan1°.tan2°…….tan89°]=

$10 [\tan 1 ° . \tan 2 ° ....... \tan 89 °] =$

A
2
B
0
C
10
D
1

Solution:

$10 [\tan 1 ° . \tan 2 ° ..... \tan 45 ° .... \tan (90 ° - 2 °) \tan (90 ° - 1 °)]$

$10 [\tan 1 ° . \tan 2 ° ..... \tan 45 ° .... \cot 2 ° \cdot \cot 1 °]$

$10 [\tan 1 ° \tan 2 ° ....1.... \frac{1}{\tan 2 °} . \frac{1}{\tan 1 °}] = 10$

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