Mathematics12+23+34=

$\frac{1}{2} + \frac{2}{3} + \frac{3}{4} =$

A
$\frac{6}{9}$
B
$\frac{23}{6}$
C
$\frac{23}{12}$
D
$\frac{6}{24}$

Solution:

$\frac{1}{2} + \frac{2}{3} + \frac{3}{4} = \frac{6 + 8 + 9}{12} = \frac{23}{12}$

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