1474÷272=

$\frac{\sqrt{147}}{4} \div \frac{\sqrt{27}}{2} =$

A
$\frac{7}{6}$
B
$\frac{7}{5}$
C
$\frac{7}{4}$
D
$\frac{7}{3}$

Solution:

$\frac{\sqrt{147}}{4} \div \frac{\sqrt{27}}{2} = \frac{\sqrt{49 x 3}}{4} \div \frac{\sqrt{9 x 3}}{2}$

$= \frac{\sqrt{49} x \sqrt{3}}{4} \div \frac{\sqrt{9} \times \sqrt{3}}{2} [\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}]$

$= \frac{7 \sqrt{3}}{4} \div \frac{3 \sqrt{3}}{2}$

$= \frac{14 \sqrt{3}}{12 \sqrt{3}}$

$= \frac{7}{6}$

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