∫−22 |xcos⁡πx|dx is equal to

22|xcosπx|dx is equal to

  1. A

    8π

  2. B

    4π

  3. C

    2π

  4. D

    1π

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    Solution:

    Since ,I=22|xcosπx|dx=202|xcosπx|dx

    =2012|xcosπx|dx+1232|xcosπx|dx+322|xcosπx|dx

    =8π

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