∫23 2x2x4+3×2+1dx is equal to

232x2x4+3x2+1dx is equal to

  1. A

    15tan1754+tan1556

  2. B

    25tan1554+tan1526

  3. C

    15tan17554+tan1556

  4. D

    4

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    Solution:

    Let,

    I=232x2x4+3x2+1dx=23x2+1x4+3x2+1dx+23x21dxx4+3x2+1=231+1/x2dx[x(1/x)]2+5+2311/x2dx[x+(1/x)]2+1

    In 1st put x1x=t,  in 2nd  put  x+1x=y

     I=3/28/3dtt2+5+5/210/3dyy2+1=15tan1835tan1325+tan1103tan152=15tan17554+tan1556

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