Search for: ∫−23 x2−1dx is equal to ∫−23 x2−1dx is equal to A3B13C173D283 Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:∫−23 x2−1dx=∫−2−1 x2−1dx+∫−11 x2−1dx+∫13 x2−1dx[here, modulus function will change at the points, ,when x2−1=0i. . , at x=±1] so,I=∫−2−1 x2−1dx+∫−11 1−x2dx+∫13 x2−1dx=x33−x−2−1+x−x33−11+x33−x13=23+23+23+23+6+23=283 Related content Test your English Vocabulary CUET Exam Dates 2024 – Application Form, Fees, Eligibility CBSE Class 12 IP Answer Key 2024,Informatics Practices Paper Solution For SET 1, 2, 3, 4 CUET UG Cut Off 2024, Category, Universities and Colleges Wise Expected Cut Off Modal Verbs Helping Verbs Letter To Your Friend About Your School Trip Action Verbs CUET 2024 – List of Colleges and Participating Universities Accepting CUET Exam Score SRMJEEE Online Test Series – Practice Papers